x^2=326

Solution for x^2=326 equation:

x^2=326

We move all terms to the left:

x^2-(326)=0

a = 1; b = 0; c = -326;
Δ = b2-4ac
Δ = 02-4·1·(-326)
Δ = 1304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1304}=\sqrt{4*326}=\sqrt{4}*\sqrt{326}=2\sqrt{326}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{326}}{2*1}=\frac{0-2\sqrt{326}}{2}
=-\frac{2\sqrt{326}}{2}
=-\sqrt{326}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{326}}{2*1}=\frac{0+2\sqrt{326}}{2}
=\frac{2\sqrt{326}}{2}
=\sqrt{326}
$